The amount of Mixture 1 equals the amount of Mixture 2. The amount to
be removed equals the amount to be added.
EXAMPLE:How much antifreeze which is 30% alcohol must be removed
from a 48-ounce container and replaced with water to make 48 ounces of a
solution which is 20% alcohol?
SOLUTION:
GOAL: You are being asked to find how much of the alcohol solution must
be removed and how much water must be added to dilute the solution.
STRATEGY: Letx¼the amount of the alcohol solution to be removed and
the amount of water to be added; then
Mixture 1Amount to beþAmount of weaker mixture¼Mixture 2
removed to be added
30%(48)30%(x)þ0%(x)*¼20%(48)
*Since the water has no alcohol, 0% is used.
IMPLEMENTATION: Solve the equation:
30 %ð 48 Þ 30 %xþ 0 %ðxÞ¼ 20 %ð 48 Þ
0 : 30 ð 48 Þ 0 : 30 %x¼ 0 : 20 ð 48 Þ
14 : 4 0 : 3 x¼ 9 : 6
14 : 4 14 : 4 0 : 30 x¼ 9 : 6 14 : 4
0 : 30 x¼ 4 : 8
0 : 301 x
0 : 301
¼
4 : 8
0 : 30
x¼16 ounces
Hence to dilute the 30% solution, 16 ounces must be removed and
16 ounces of water must be added to make 48 ounces of a 20% solution.
LESSON 14 Solving Mixture Problems 151