EVALUATION: Check the equation:
30 %ð 48 Þ 30 %ðxÞþ 0 %x¼ 20 %ð 48 Þ
30 %ð 48 Þ 30 %ð 16 Þþ 0 %ð 16 Þ¼ 20 %ð 48 Þ
14 : 4 4 : 8 ¼ 9 : 6
9 : 6 ¼ 9 : 6
The second type of mixture problems consists of mixing two items such as
coffees, teas, candy, etc., with different prices. These problems are similar to
the previous ones. You can use this basic equation:
Item 1Its priceþItem 2Its price¼MixtureIts price
EXAMPLE:A merchant mixes some coffee costing $4 a pound with some
coffee costing $3 a pound. How much of each must be used in order to make
20 pounds of mixture costing $3.75 per pound?
SOLUTION:
GOAL: You are being asked to find how much of each coffee must be mixed
together to get 20 pounds of coffee costing $3.75.
STRATEGY: Letx¼the amount of the $4 coffee and 20x¼the amount
of the $3 coffee; then
Amount Price ¼ Total value
Coffee 1 x $4 4(x)
Coffee 2 20 x $3 3(20x)
Mixture 20 $3.75 3.75(20)
The equation is 4xþ3(20x)¼3.75(20).
152 LESSON 14 Solving Mixture Problems