10.5. Applications of Parametric Equations http://www.ck12.org
clockwise. Write parametric equations that model Nikki’s position over time. Where will Nikki be three minutes
from now?
Answers:
- A football field is 100 yards or 300 feet. The parametric equations for a football thrown from (300, 0) back to the
origin at speedvare:
x=−t·v·cos
(π
4
)
+ 300
y=^12 ·(− 32 )·t^2 +t·v·sin
(π
4
)
Substituting the point (0, 0) in for(x,y)produces a system of two equations with two variablesv,t.
0 =−t·v·cos
(π
4
)
+ 300
0 =^12 ·(− 32 )·t^2 +t·v·sin
(π
4
)
You can solve this system many different ways.
t=^5
√ 3
2 ≈^4.^3 seconds,v=^40
√
6 ≈ 97. 98 f t/s
In order for someone to throw a football at a 45◦angle all the way across a football field, they would need to throw
at about 98f t/swhich is about 66.8 mph.
(^981) secf eet· (^36001) hoursec· 52801 milef eet≈ 661. (^8) hourmiles
- Calculate the velocity of each person and of the wind in feet per second:
67 miles
1 hour ·
1 hour
3600 sec·
5280 f eet
1 mile ≈^98.^27 f t/sec
60 miles
1 hour ·
1 hour
3600 sec·
5280 f eet
1 mile =^88 f t/sec
4 miles
1 hour·
1 hour
3600 sec·
5280 f eet
1 mile ≈^5.^87 f t/sec
The location of Danny’s ball can be described with the following parametric equations (in radians). Note that the
wind simply adds a linear term.
x 1 =−t· 98. 27 ·cos
(π
4
)
+ 300 + 5. 87 t
y 1 =^12 ·(− 32 )·t^2 +t· 98. 27 ·sin
(π
4
)
The location of Johnny’s ball can be described with the following parametric equations.
x 2 =t· 88 ·cos
( 5 π
18
)
+ 5. 87 t
y 2 =^12 ·(− 32 )·t^2 +t· 88 ·sin
( 5 π
18