http://www.ck12.org Chapter 14. Concepts of Calculus
- Megan is being extremely liberal with the idea of “=∞” because what she really means for the two limits is
“DNE”. For the function evaluated at 2 the correct response is “undefined”. Two things that do not exist cannot be
equal to one another.
a. xlim→ 1 −( 2 x− 1 ) = 2 · 1 − 1 = 2 − 1 = 1
b.x→−lim 3 +(x+^22 )=− 32 + 2 =−^21 =− 2
c. limx→ 2 +
(x (^3) − 8
x− 2
)
=xlim→ 2 +
((x− 2 )(x (^2) + 2 x+ 4 )
(x− 2 )
)
=xlim→ 2 +(x^2 + 2 x+ 4 ) = 22 + 2 · 2 + 4 = 12
- Use the definition of continuity.
- limx→ 1 −f(x) = (− 1 )^2 − 1 = 1 − 1 = 0
- f(− 1 ) = 3
- x→−lim 1 +f(x) =− 1 + 3 = 2
xlim→a−f(x)^6 =f(a)^6 =xlim→a+f(x)so this function is discontinuous atx=−1. It is continuous everywhere else.
Practice
Evaluate the following limits.
- limx→ 6 −( 3 x^2 − 4 )
- limx→ 0 −^3 x−x^1
- limx→ 0 +^3 x−x^1
- limx→ 0 +|xx|
- limx→ 0 −|xx|
- limx→ 0 +
√x
√ 1 +√x− 1
Consider
f(x) =
2 x^2 − 1 x< 1
1 x= 1
−x+ 2 1 <x
- What is limx→ 1 −f(x)?
- What is limx→ 1 +f(x)?
- Isf(x)continuous atx=1?
Consider
g(x) =
4 x^2 + 2 x− 1 x<− 2
8 x=− 2
− 3 x+ 5 − 2 <x