We can re-statethe problemin termsof a differentialequationthat satisfiesan initialcondition.
with
By integratingthe right side of the differentialequationwe have
as the generalsolution.Substitutingthe conditionthat gives
Hence is theparticularsolutionof the originalequation satis-
fyingtheinitialcondition
Finally, sincewe are interestedin the valuef (-2), we put -2 into our expressionfor f and obtain:
LessonSummary
- We foundgeneralsolutionsof differentialequations.
- We usedinitialconditionsto find particularsolutionsof differentialequations.
ReviewQuestions
In problems#1–3,solvethe differentialequationfor
In problems#4–7,solvethe differentialequationfor giventhe initialcondition.
- and
- and