CK12 Calculus - Single Variable

(Marvins-Underground-K-12) #1
FromTheorem4.1 we havethat is an antiderivativeof Hence, and in particular,
Hence,by substitutionwe have

Notethat Hencewe have

and by our definitionof we have

This theoremallowsus to find for positivefunctionsa rectanglethat has base and height such
that the area of the rectangleis the sameas the area givenby In otherwords, is the
averagefunctionvalueover

ReviewQuestions
In problems#1–8,use antiderivativesto computethe definiteintegral.

























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