Figure7b
Solution:
Let the -axispassthroughthe apexof the pyramid,as shownin Figure(7a). At any point in the interval
the cross-sectionalarea is a square.If is the lengthof the sidesof any arbitrarysquare,then,by
similartriangles(Figure7b),
b
Sincethe cross-sectionalarea at is
Usingthe volumeformula,
V
Using -substitutionto integrate,we eventuallyget
V
Thereforethe volumeof the pyramidis , whichagreeswith the standardformula.
Volumesof Solidsof Revolution
The Methodof Disks