Cracking The SAT Premium

(Marvins-Underground-K-12) #1

  1. D Start by figuring out what percent of the houses do not have two-car garages. Since 60% of the


houses  with    garages have    two-car garages,    40% of  the houses  with    garages do  not have    two-car

garages.    In  other   words,  40% of  80% of  the houses  do  not have    two-car garages.    Translate   that

into    math    to  get     of  the houses. The problem tells   us  that    56  houses  do  not have    two-

car garages,    which   means   32% of  the houses  equals  56. Translating into    math    gives   us      ×   x

=   56. Solve   for x,  and you’ll  get 175,    which   is  (D).


  1. D Let’s try out the answers and see which one works. Start with (B). If the watchmaker made 21


watches on  Tuesday,    then    he  must    have    made    17  watches on  Monday. We  know    that    he  should

have    made    16% more    watches on  Tuesday than    on  Monday, so  let’s   use the percent change

formula     to  see if  we  get 16%:    ≈   23.5%,  which   is  too big.    Eliminate

(B).    We  want    the 4   watches to  be  a   smaller percent of  the total,  so  we  need    a   bigger  total.  Try a

bigger  answer  choice, like    (D).    If  he  made    29  watches on  Tuesday,    then    he  made    25  watches on

Monday. Now the percent change  is   =   0.16    =   16%,    which   is  exactly     what    we  wanted.

Therefore,  (D) is  the correct answer.
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