Cracking The SAT Premium

(Marvins-Underground-K-12) #1
answer  choices,    make    t   =   1   in  (A) and (D) and eliminate   any choice  that    does    not equal

1,287.06.   Only    (A) works.


  1. B You can start by Plugging In a value for x; try x = 4. Because angle AOB is 120° and the


triangle    is  isosceles,  angles  A   and B   are each    30°.    Cut triangle    AOB in  half    to  make    two 30-

60-90   triangles   with    a   hypotenuse  of  4   and legs    of  2   and 2 . The leg with    length  2   lies

on  chord   AB. Double  it  to  get the total   length: 4   or  just     x, which   is(B)   when    you put x

=   4   into    the answer  choices.


  1. C Whenever there are variables in the question and in the answer choices, think Plugging In.


The question    states  the value   of  g,  but it  is  a   constant    and a   weird   one at  that.   Pick    numbers

for all the variables   that    will    make    the math    more    straightforward.    If  v   =   4   and g   =   2,  then    t

=    =   4   ·   sin(θ),     and    R    =   =   8   ·

sin(2θ) =   8   ·   sin(2θ).    Plug     these   values  into    the     answer  choices     to  see     which   equation

works.  Choice  (A) becomes 4   =    .  Simplify    the right   side    of  the equation

to  get 4   =    ,  or  4   =    .  This    will    not simplify    further,    so  eliminate

(A).    Choice  (B) becomes 4   =    .  Simplify    the right   side    of  the equation    to

get  4   =   or  4   =   .   Eliminate   (B).    Choice  (C)     becomes     4   =  

. Distribute the 2 to get 4 = . Reduce the equation


to  get or  4   =       or  4   =   4.  The correct answer  is  (C).



  1. D ia = 1 when a is a multiple of 4. Using your exponents rules, 413 + x must also be a
    multiple of 4. Plug in the answers and look for what makes 413 + x a multiple of 4. Only
    (D) works.




  2. C The zero of g is the value of the variable, in this case x, when the equation is set to 0. This




is  also    called  the root    or  solution    of  an  equation.   Set the equation    to  0   to  get 0   =   2x^2    –   dx  –


  1. Plug 6 in for x to get 0 = 2(6^2 ) – d(6) – 6. Simplify the equation to get 0 = 72 – 6d – 6, or

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