AP Physics C 2017

Second, we break the F (^) push vector into components that line up with the horizontal and vertical axes.
We can now move on to Step 3 , writing equations for the net force in each direction:
Now we can plug in our known values into these equations and solve for the acceleration of the block.
First, we solve for the right–left direction:
Next, we solve for the up–down direction. Notice that the block is in equilibrium in this direction—it is
neither flying off the table nor being pushed through it—so we know that the net force in this direction
must equal 0.
So the acceleration of the block is simply 2.2 m/s^2 to the right.