Math & Science ACT Workuot

(Marvins-Underground-K-12) #1
use, sinθ = , so sin33° = . Using the provided information, =

0.545, and south = 0.545·550 ≈ 300. Choice (G) is the only answer choice with the correct

due south distance, so you can stop there. If you prefer to start by finding the distance due

east, use sinθ = , so sin 33° = . Using the provided information, =

0.839, and east = 0.839 · 550 ≈ 461. If you picked (K), be careful: The sides are reversed in

this answer choice.

52 . J This is a difficult problem, but it is easy to solve if you know a few basic trig facts. First,

remember “All Students Take Calculus.” This is a helpful reminder of which quadrants have

positive functions. In Quadrant I, all trig functions are positive. In Quadrant II, sine is

positive. In Quadrant III, tangent is positive. In Quadrant IV, cosine is positive. This is

helpful because it tells us that a tangent value in Quadrant IV must be negative, eliminating

(F) and (G). Then, because tanθ = , our final value cannot include the

hypotenuse 25, eliminating (H) and (K) and leaving only (J).
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