CK-12-Physics - Intermediate

(Marvins-Underground-K-12) #1

http://www.ck12.org Chapter 16. Electric Potential


The net force on the electron must be zero, thus


∑F=^0 →eF=mg→F=


mg
e
but F=eE→

mg
e
=eE→E=

mg
e^2


E=


( 9. 11 × 10 −^31 kg)

(


9. 81 ms 2

)


( 1. 60 × 10 −^19 C)^2


= 3. 49 × 108


V


m

http://www.youtube.com/watch?v=wT9AsY79f1k


The Electron-Volt


It is often convenient when dealing with small particles such as electrons, protons, and ions to express the energy
of these particles with a smaller unit of measure. The electron-volt is defined as the change in potential energy that
an electron acquires when moving through a potential difference of 1V,or equivalently, its change in kinetic energy
after moving through a potential difference of 1V.


That is,PE=eV= ( 1. 60 × 10 −^19 C)( 1. 00 V) = 1. 60 × 10 −^19 J.


The energy 1. 60 × 10 −^19 Jis defined as one electron-volt. We write one-electron-volt as 1eV= 1. 60 × 10 −^19 J.


Check Your Understanding



  1. What is the change in kinetic energyKEwhen an electron is released at the negative plate of a parallel plate
    conductor with a potential difference of 3,500 V? Express your answer in eV.


Answer: The electron is repelled at the negative plate and therefore gains kinetic energy (and loses potential energy).
The change inKEis positive and equal to


1 eV
1 V

=


x eV
3 , 500 V
→x= 3 , 500 eV

∆KE= 3 , 500 eV
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