http://www.ck12.org Chapter 2. One-Dimensional Motion
between two and three seconds. Using the definition of acceleration,a=∆∆vt; substitution gives: 4.5 m/s^2 =11 m/s∆t.
Rearranging and solving, gives:
∆t= 4 11 m/s.5 m/s 2 = 2 .4 s
http://www.ck12.org Chapter 2. One-Dimensional Motion
between two and three seconds. Using the definition of acceleration,a=∆∆vt; substitution gives: 4.5 m/s^2 =11 m/s∆t.
Rearranging and solving, gives:
∆t= 4 11 m/s.5 m/s 2 = 2 .4 s