CK-12-Physics - Intermediate

(Marvins-Underground-K-12) #1

22.4. Mass-Energy Equivalence http://www.ck12.org


We can also show that the relativistic equationE=mc^2 +KEreduces to the Newtonian equation for the kinetic
energy whenvc. We show this result in the following example.


Illustrative Example 23.2.2


Show that, in the casevc, the equationE=mc^2 +KEreduces toKE=^12 mv^2.


Solution:


Using the binomial expansion for√^1
1 +vc^22


whenvc,Ecan be expressed as follows:

E= mc
√^2
1 −vc^22


≈mc^2

(


1 +v

2
2 c^2 +...

)


, where additional terms in the expansion add smaller and more negligible terms,

and so are ignored.


Substituting the above approximation forEin the equationE=mc^2 +KE, we have


mc^2

(


1 +


v^2
2 c^2

+...


)


=mc^2 +KE→mc^2 +

1


2


mv^2 =mc^2 +KE→

KE=


1


2


mv^2

Check Your Understanding



  1. True or False:


The equation for relativistic kinetic energy for an object of massmtraveling with speedvcan be found by substituting
√m
1 −vc^22


for the massminto the equationKE=^12 mv^2.

Answer: False. We can see from the equationE=mc^2 +KEand Example 23.2.2 that the relativistic form for
kinetic energy is not arrived at in the same way as the relativistic equations for force and momentum.


2a. How much energy is released if a proton of mass 1. 67 × 10 −^27 kgis completely converted to energy?


Solution:


Using the rest energy of a proton, we have


E=mc^2 = ( 1. 67 × 10 −^27 kg)( 3. 00 × 108 )^2 = 1. 50 × 10 −^10 J


2b. Express your answer in electron-volts(eV).


Answer: Recall that 1. 00 eV= 1. 60 × 10 −^19 J, therefore



  1. 50 × 10 −^10 J

  2. 60 × 10 −^19 J=^0.^9375 ×^10


(^9) eV or 938 MeV
Relative velocity
We began our discussion of relativity by stating that the results of Maxwell’s equations, that light must always travel
at a constant velocitycin vacuum, contradicted the results of Galilean relative velocity. Namely, relative velocity
could not be calculated by the vector addition of velocities, that is~vr=~v 1 +~v 2. We have seen that in order to preserve
Galilean relativity, the expressions for both time and space needed to be changed. Since observers in different inertial
frames measure different times and different lengths, the equation for calculating Galilean relative velocity must also
change. Einstein showed how the Galilean equation for relative velocities must be changed in order for light (and
the theory of electromagnetism) to remain consistent with Galilean relativity.

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