2.7. Linearization and Newton’s Method http://www.ck12.org
Figure 11
xn+ 1 =xn−x(^3) n+xn− 1
3 x^2 n+ 1
x 2 = 0. 6 −(^0.^6 )
(^3) +( 0. 6 )− 1
3 ( 0. 6 )^2 + 1
= 0. 6884615.
Using the recursion relation again to findx 3 , we get
x 3 = 0. 6836403.
We conclude that the solution to the equationx^3 +x− 1 =0 is about 0.6836403.
Multimedia Links
For a video presentation of Newton’s method(10.0), see Math Video Tutorials by James Sousa, Newton’s method
(9:48).
MEDIA
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