CK-12-Calculus

(Marvins-Underground-K-12) #1

http://www.ck12.org Chapter 5. Applications of Definite Integrals


Figure 18
Solution:
Sincey=x^3 / 2 ,


dy
dx=

3


2 x

1 / (^2).
Using the formula above, we get
∫b
a



1 +[f′(x)]^2 dx=

∫ 3
1


1 +


[ 3


2 x

1 / 2

] 2


dx

=

∫ 3
1


1 +^94 xdx.

Usingu−substitution by lettingu= 1 +^94 x, thendu=^94 dx.Substituting, and remembering to change the limits of
integration,


L=^49


∫ 31 / 4
13 / 4

√udu

= 278


[


u^3 /^2

] 31 / 4


13 / 4
≈ 4. 65.
Free download pdf