6.5. Derivatives and Integrals Involving Inverse Trigonometric Functions http://www.ck12.org
6.5 Derivatives and Integrals Involving Inverse Trigonometric Functions
Learning Objectives
A student will be able to:
- Learn the basic properties inverse trigonometric functions.
- Learn how to use the derivative formula to use them to find derivatives of inverse trigonometric functions.
- Learn to solve certain integrals involving inverse trigonometric functions.
A Quick Algebraic Review of Inverse Trigonometric Functions
You already know what a trigonometric function is, but what is an inverse trigonometric function? If we ask what is
sin(π/ 6 )equal to, the answer is( 1 / 2 ).That is simple enough. But what if we ask what angle has a sine of( 1 / 2 )?
That is an inverse trigonometric function. So we say sin(π/ 6 ) = ( 1 / 2 ),but sin−^1 ( 1 / 2 ) = (π/ 6 ).The “sin−^1 ” is the
notation for the inverse of the sine function. For every one of the six trigonometric functions there is an associated
inverse function. They are denoted by
sin−^1 x,cos−^1 x,tan−^1 x,sec−^1 x,csc−^1 x,cot−^1 xAlternatively, you may see the following notations for the above inverses, respectively,
arcsinx,arccosx,arctanx,arcsecx,arccscx,arccotxSince all trigonometric functions are periodic functions, they do not pass the horizontal line test. Therefore they are
not one-to-one functions. The table below provides a brief summary of their definitions and basic properties. We
will restrict our study to the first four functions; the remaining two, csc−^1 and cot−^1 ,are of lesser importance (in
most applications) and will be left for the exercises.
TABLE6.1:
Inverse Function Domain Range Basic Properties
sin−^1 − 1 ≤x≤ 1 − 2 π≤y≤π 2 sin(sin−^1 (x)) =x
cos−^1 − 1 ≤x≤ 1 0 ≤y≤π cos−^1 (cosx) =
cos(cos−^1 (x)) =x
tan−^1 allR (− 2 π,π 2 ) tan−^1 (tanx) =
tan(tan−^1 (x)) =x
sec−^1 (−∞,− 1 ]∪[ 1 ,+∞) [ 0 ,π 2 )∪(π 2 ,π] sec−^1 (secx) =
sec(sec−^1 (x)) =x