CK-12-Calculus

(Marvins-Underground-K-12) #1

8.2. Infinite Series http://www.ck12.org


Example 5
Determine if the series 7+^78 + 872 + 873 +...+ 8 i^7 − 1 +...converges or diverges. If it converges, find the sum of the
series.
Solution
The series is a geometric series that can be written as∑∞k= 17 (^18 )k−^1. Thena=7 and the ratior=^18. Because∣∣^18 ∣∣< 1
, the series converges. The sum of the series is 1 −ar= 1 −^718 =^778 =8.


Example 6
Determine if the series∑+k=∞ 19 k−^1 converges or diverges. If it converges, find the sum of the series.
Solution
The series is a geometric series witha=1 and the ratior=9. Because| 9 |>1, the series diverges.
Example 7


Determine if^34 + 432 + 433 +...+^3 (− 4 k^1 )k+...converges or diverges. If it converges, find the sum of the series.
Solution
If we rewrite the series in terms of powers ofk, the series looks like this:


3 (− 1 )^1


41 +


3 (− 1 )^2


42 +


3 (− 1 )^3


43 +...+


3 (− 1 )k
4 k +...=^3

(


−^14


) 1


+ 3


(


−^14


) 2


+...+ 3


(


−^14


)k
+....

It looks like a geometric series witha=3 andr=−^14 .Since


∣∣


−^14


∣∣


=^14 <1, the series converges.
However, if we write the definition of a geometric series fora=3 andr=−^14 , the series looks like this:


+∞
k∑= 13

(


−^14


k− 1 )
= 3

(


−^14


) 0


+ 3


(


−^14


) 1


+ 3


(


−^14


) 2


+...


= 3 + 3


(


−^14


) 1


+ 3


(


−^14


) 2


+...


The original problem,^3 (− 411 )^1 +^3 (− 421 )^2 +^3 (− 431 )^3 +...+^3 (− 4 k^1 )k+..., does not have the leading term of 3. This does
not affect the convergence but will affect the sum of the series. We need to subtract 3 from the sum of the series
3 + 3 (−^14 )^1 + 3 (−^14 )^2 +...to get the sum of^3 (− 411 )^1 +^3 (− 421 )^2 +^3 (− 431 )^3 +...+^3 (− 4 k^1 )k+....


The sum of the series is: 1 −ar− 3 = 1 −(^3 − (^14) )− 3 =^354 − 3 =^125 − 3 =^125 −^155 =−^35.
Other Convergent Series
There are other infinite series that will converge.
Example 8
Determine if∑+k=∞ 1 (^2 k−k+^21 )converges or diverges. If it converges, find the sum.
Solution
Thenth partial sumsnis:

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