CK-12-Chemistry Intermediate

(Marvins-Underground-K-12) #1

http://www.ck12.org Chapter 20. Entropy and Free Energy


∆H° for the reaction is +206.1 kJ/mol, while∆S° is +215 J/K•mol. Calculate∆G° for this reaction at 25°C and
determine whether it is spontaneous at that temperature.


Step 1: List the known values and plan the problem.


Known



  • ∆H° = 206.1 kJ/mol

  • ∆S° = 215 J/K•mol = 0.215 kJ/K•mol

  • T = 25°C = 298 K


Unknown



  • ∆G° =? kJ/mol


Prior to substitution into the Gibbs free energy equation, the entropy change is converted to kJ/K•mol and the
temperature to Kelvins.


Step 2: Solve.


∆G° =∆H° - T∆S° = 206.1 kJ/mol - 298 K(0.215 kJ/K•mol)
∆G° = +142.0 kJ/mol

The resulting positive value of∆G indicates that the reaction is not spontaneous at 25°C.


Step 3: Think about your result.


The unfavorable increase in enthalpy outweighed the favorable increase in entropy. The reaction will be spontaneous
only at a more elevated temperature.


Practice Problem


  1. For the reaction in Sample Problem 20.1, calculate∆G at a temperature of 1200. K. Is the reaction spontaneous
    at that temperature?


Available values for enthalpy and entropy changes are generally measured at the standard conditions of 25°C and 1
atm pressure. They are slightly temperature dependent, so we must use caution when calculating specific∆G values
at temperatures other than 25°C, as in the practice problem above. However, since the values for∆H and∆S do not
change a great deal, the tabulated values can safely be used when making general predictions about the spontaneity
of a reaction at various temperatures.


Lesson Summary



  • A reaction or process is considered to be spontaneous when the formation of products is favored at a given set
    of conditions.

  • Spontaneous reactions release free energy, which can be used to do work.

  • A mathematical combination of enthalpy change and entropy change allows the change in free energy to be
    calculated. A reaction with a negative value for∆G releases free energy and is thus spontaneous. A reaction
    with a positive∆G is nonspontaneous and will not favor the products.

  • Some reactions may be spontaneous at some temperatures and nonspontaneous at other temperatures.

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