http://www.ck12.org Chapter 6. Normal Distribution Curves
Example A
Use technology to determine the mean and standard deviation of the following bowling averages, which represent a
small population.
54 88 49 44 96 72 46 58 79
92 44 50 102 80 72 66 64 61
60 56 48 52 54 60 64 72 68
64 60 56 52 55 60 62 64 68
From the list, you can see that the mean of the bowling averages is approximately 63.7 and that the standard deviation
is approximately 14.1.
Now you can represent the data that your teacher gave to you for the bowling averages of the players in your league
on anormal distribution curve. Again, the mean bowling score was 63.7, and the standard deviation was 14.1.
From the normal distribution curve, you can see that your average bowling score of 70 is within 1 standard deviation
of the mean. You can also see that 68% of all the data is within 1 standard deviation of the mean, so you did very
well bowling this semester. You should definitely return to the league next semester.
Example B
Use technology to determine the variance of the bowling averages in Example A.
To use technology to calculate the variance involves naming the lists according to the operations that you need to do
in order to determine the correct values. In addition, you can use the CATALOG menu of the calculator to determine