CK-12-Basic Probability and Statistics Concepts - A Full Course

(Marvins-Underground-K-12) #1

1.4. Mutually Exclusive Events http://www.ck12.org


HHH


HT H


HHT


HT T


T HH


T HT


T T H


T T T


It’s apparent from the list of possible outcomes that there are 3 ways to get 1 head and 3 ways to get 2 heads. Since
getting 1 head and getting 2 heads cannot occur at the same time, these events are mutually exclusive. Suppose that
eventAis getting 1 head and eventBis getting 2 heads. The probability of getting 1 or 2 heads can then be calculated
as follows:


P(A) =


3


8


P(B) =


3


8


P(AorB) =P(A)+P(B)
P(A∪B) =P(A)+P(B)

P(A∪B) =

3


8


+


3


8


P(A∪B) =


6


8


P(A∪B) =


3


4


P(AandB) = 0

Practice



  1. 2 dice are tossed. What is the probability of obtaining a sum equal to 6?

  2. 2 dice are tossed. What is the probability of obtaining a sum less than 6?

  3. 2 dice are tossed. What is the probability of obtaining a sum greater than 6?

  4. 2 dice are tossed. What is the probability of obtaining a sum of at least 6?

  5. Thomas bought a bag of jelly beans that contained 10 red jelly beans, 15 blue jelly beans, and 12 green jelly
    beans. What is the probability of Thomas reaching into the bag and pulling out a blue or green jelly bean?

  6. A card is chosen at random from a standard deck of cards. What is the probability that the card chosen is a
    heart or spade? Are these events mutually exclusive?

  7. 3 coins are tossed simultaneously. What is the probability of getting 3 heads or 3 tails? Are these events
    mutually exclusive?

  8. In question 7, what is the probability of getting 3 headsand3 tails when tossing the 3 coins simultaneously?

  9. Are randomly choosing a person who is left-handed and randomly choosing a person who is right-handed
    mutually exclusive events? Explain your answer.

  10. Suppose 2 events are mutually exclusive events. If one of the events is randomly choosing a boy from the
    freshman class of a high school, what could the other event be? Explain your answer.

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