Peoples Physics Book Version-2

http://www.ck12.org Chapter 16. Electric Circuits Advanced Topics Version 2

e) We now want to find the output voltage given an input voltage of 0.75V at pointA. Though the numbers are
different, it is the same process as solving it when the input voltage was 0.5V. First we must find the current and the
total resistance. We then use these values to solve for the output voltage.

V=IR⇒

V

R

=I⇒I=

.75V

10 Ω

=.075A

The total resistance remains unchanged.

Rtotal=R 1 +R 2 = 10 Ω+ 100 Ω= 110 Ω

So the new output voltage is

V=IR=.075A× 110 Ω= 8 .25V

f) This is a simple division problem. The output voltage divided by the input voltage will give us the factor by which
the output voltage is greater than the input voltage.

8 .25V

.75V

= 11