Peoples Physics Concepts

(Marvins-Underground-K-12) #1

http://www.ck12.org Chapter 12. Electricity


charge will be radially symmetric i.e., the strength of the field only depends on the distance,r, from the charge, not
the direction; the lengths of the arrows represent the strength of the field.

Example 1

Question: Calculate the electric field a distance of 4.0mm away from a− 2. 0 μC charge. Then, calculate the force
on a− 8. 0 μC charge placed at this point.
Answer: To calculate the electric field we will use the equation

E=

kq
r^2
Before we solve for the electric field by plugging in the values, we convert all of the values to the same units.

4 .0mm×
1m
1000mm

=.004m

− 2. 0 μC×

1C


1000000 μC

=− 2. 0 × 10 −^6 C


Now that we have consistent units we can solve the problem.

E=


kq
r^2

=


9 × 109 Nm^2 /C^2 ×− 2. 0 × 10 −^6 C
(.004m)^2

=− 1. 1 × 109 N/C


To solve for the force at the point we will use the equation
F=Eq
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