Peoples Physics Concepts

13.2. Ohm’s Law http://www.ck12.org

Solution

Since the light bulb is the only object in the circuit, we know the voltage drop across the light bulb is equal to that

of the battery. Therefore, we can use Ohm’s law to solve for the current in the resistor.

V=IR

I=

V

R

I=

1 .5 V

2 Ω

I=.75 A

Now we can determine the power of the bulb.

P=IV

P=.75 A∗ 1 .5 V

P= 1 .13 W

Watch this Explanation

MEDIA

Click image to the left for use the URL below.

URL: http://www.ck12.org/flx/render/embeddedobject/315

Simulation