CK-12 Geometry - Second Edition

(Marvins-Underground-K-12) #1

http://www.ck12.org Chapter 3. Parallel and Perpendicular Lines


Solution:First, graph the line and point. Second determine the equation of the perpendicular line. The opposite
sign and reciprocal of^13 is -3, so that is the slope. We know the line must go through the given point, (1, 5), so use
that to find they−intercept.


y=− 3 x+b
5 =− 3 ( 1 )+b The equation of the line isy=− 3 x+ 8.
8 =b

Next, we need to find the point of intersection of these two lines. By graphing them on the same axes, we can see
that the point of intersection is (3, -1), the green point.


Finally, plug (1, 5) and (3,-1) into the distance formula to find the shortest distance.

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