CK-12 Geometry-Concepts

(Marvins-Underground-K-12) #1

http://www.ck12.org Chapter 3. Parallel and Perpendicular Lines



  • 2x− 3 y=6 and 3x+ 2 y= 6

  • 5x+ 2 y=−4 and 5x+ 2 y= 8

  • x− 3 y=−3 andx+ 3 y= 9

  • x+y=6 and 4x+ 4 y=− 16



  1. Find the equation of the line that is parallel toy=^14 x+3 and passes through (8, -7).

  2. Find the equation of the lines below and determine if they are parallel.


Answers:



  1. First change all equations intoy=mx+bform so that you can easily compare the slopes by looking at the values
    ofm. Thethirdandfifthpair of lines are the only ones that are parallel.

  2. We know that parallel lines have the same slope, so the line will have a slope of^14. Now, we need to find the
    y−intercept. Plug in 8 forxand -7 foryto solve for thenew y−intercept(b).


− 7 =


1


4


( 8 )+b
− 7 = 2 +b
− 9 =b

The equation of the parallel line isy=^14 x−9.



  1. The top line has ay−intercept of 1. From there, use “rise over run” to find the slope. From they−intercept, if
    you go up 1 and over 2, you hit the line again,m=^12. The equation isy=^12 x+1.


For the second line, they−intercept is -3. The “rise” is 1 and the “run” is 2 making the slope^12. The equation of this
line isy=^12 x−3.


The lines areparallelbecause they have the same slope.


Interactive Practice

Free download pdf