CK-12 Geometry-Concepts

(Marvins-Underground-K-12) #1

5.4. Medians http://www.ck12.org


1


2


BH=HForBH= 2 HF HC=

2


3


DCor

3


2


HC=DC


3 x+ 6 = 2 ( 2 x− 1 )

3


2


( 2 y+ 8 ) = 5 y− 16
3 x+ 6 = 4 x− 2 3 y+ 12 = 5 y− 16
8 =x 28 = 2 y


  1. This statement is true. By definition, a median intersects a side of a triangle at its midpoint. Midpoints divide
    segments into two equal parts.


Interactive Practice


MEDIA


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For questions 1-4, find the equation of each median, from vertexAto the opposite side,BC.


1.A( 9 , 5 ),B( 2 , 5 ),C( 4 , 1 )
2.A(− 2 , 3 ),B(− 3 ,− 7 ),C( 5 ,− 5 )
3.A(− 1 , 5 ),B( 0 ,− 1 ),C( 6 , 3 )
4.A( 6 ,− 3 ),B(− 5 ,− 4 ),C(− 1 ,− 8 )

For questions 5-9,B,D, andFare the midpoints of each side andGis the centroid. Find the following lengths.



  1. IfBG=5, findGEandBE

  2. IfCG=16, findGFandCF

  3. IfAD=30, findAGandGD

  4. IfGF=x, findGCandCF

  5. IfAG= 9 xandGD= 5 x−1, findxandAD.


Use 4 ABCwithA(− 2 , 9 ),B( 6 , 1 )andC(− 4 ,− 7 )for questions 10-15.

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