CK-12 Geometry-Concepts

(Marvins-Underground-K-12) #1

http://www.ck12.org Chapter 6. Polygons and Quadrilaterals



  1. To be a rectangle a shape must have four right angles. This means that the sides must be perpendicular to each
    other. From the given equations we see that the slopes are 2,−2, 2 and−2. Because the slopes are not opposite
    reciprocals of each other, the sides are not perpendicular, and the shape is not a rectangle.

  2. First, graphABCD. This will make it easier to figure out what type of quadrilateral it is. From the graph, we can
    tell this is not a parallelogram. Find the slopes ofBCandADto see if they are parallel.


Slope ofBC=^5 − 1 (−− 41 )=−^63 =− 2


Slope ofAD=^3 −− 3 (−−^51 )=−^84 =− 2


We now knowBC||AD. This is a trapezoid. To determine if it is an isosceles trapezoid, findABandCD.


AB=



(− 3 − 1 )^2 +( 3 − 5 )^2 ST=



( 4 − 1 )^2 +(− 1 −(− 5 ))^2


=



(− 4 )^2 +(− 2 )^2 =



32 + 42


=



20 = 2



5 =



25 = 5


AB 6 =CD, therefore this is only a trapezoid.



  1. We will not graph this example. Let’s find the length of all four sides.


EF=



( 5 − 11 )^2 +(− 1 −(− 3 ))^2 F G=



( 11 − 5 )^2 +(− 3 −(− 5 ))^2


=



(− 6 )^2 + 22 =



62 + 22


=



40 = 2



10 =



40 = 2



10


GH=



( 5 −(− 1 ))^2 +(− 5 −(− 3 ))^2 HE=



(− 1 − 5 )^2 +(− 3 −(− 1 ))^2


=



62 +(− 2 )^2 =



(− 6 )^2 +(− 2 )^2


=



40 = 2



10 =



40 = 2



10

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