Answers and Explanations
REVIEW QUESTIONS
1 . C
Refer to the first paragraph of this chapter.
2 . Mg2+ < P < Mg < Sr
The trends in atomic radii are as follows: Going from left to right across a period, the atomic
radii decrease because the atomic number increases. The increasing number of protons in the
nucleus will have a stronger attraction for the outermost electrons, causing them to be held
closer and more tightly to the nucleus. Going down a group, the atomic radius will increase
because there are more filled principal energy levels separating the nucleus and the outermost
electrons, shielding the attractive force between them. P has a small radius because it lies far
to the right and high in a group. The magnesium species will have smaller radii than the
strontium species because they are higher in Group II. Finally, positive ions have smaller
atomic radii than the corresponding neutral molecules, because the loss of electrons leads to
a decrease in electron-electron repulsion within the atom, which in turn allows the electrons
to move in closer to the nucleus. Therefore, Mg2+ will be smaller than Mg. Mg2+ has a smaller
radius than P because Mg2+ has no electrons in orbitals of the third principal energy level.
3 . A
The least electronegative elements are located at the bottom left of the periodic table. Cesium
has the lowest ionization energy and, likewise, it is the least electronegative. Note that
Francium (Fr) would be lower still but is not a stable, naturally occurring element.
4 . Ca3+, Ca2+, Ca+, Ca, Ca–, Ca2–
Positive ions will have smaller radii than the corresponding neutral atoms, and the greater the
positive charge, the smaller the ionic radius. Negative ions will have larger radii than the