circle with a radius r is πr^2 . The area of the circular base is 36π. If the radius of the circular
base is r, then πr^2 = 36π, r^2 = 36, and r = 6. You now have the radius. The diameter is 2(6) = 12.
Let’s call the height of the right circular cylinder h and draw a picture.The greatest possible distance between two points on the surface of the right circular
cylinder is the distance between points P and R. Use the Pythagorean theorem in right
triangle PQR to find the height h.The volume of the right circular cylinder is πr^2 h = π(6^2 )(7) = π(36)(7) = 252π.6 . E
Find a first. a + 2a + 156 = 180, 3 a + 156 = 180, 3 a = 24, and a = 8. Now use the law of sines.
. Then YZ ≈ 140.3.
7 . D
The perimeter of any polygon is the sum of the lengths of its sides. Since points S and V have
the same y-coordinate of 2, SV is parallel to the x-axis. The length of SV is the positive
difference of the x-coordinates of points V and S. The length of SV is 7 − 3 = 4 . Opposite sides
of a parallelogram are equal, so the length of TU is also 4. ST and UV are opposite sides of
parallelogram STUV, so ST and UV also have equal lengths. The perimeter of the
parallelogram is 2(4) + 2(ST). So 2(4) + 2(ST) = 14, 8 + 2(ST) = 14, 2(ST) = 6 , and ST = 3. Drop a
perpendicular line from point T to SV that meets side SV at point P.