SAT Subject Test Mathematics Level 1

(Marvins-Underground-K-12) #1

percent of 11P:


11 P    +(500%  of  11P)=11P    +5(11P)=    66P

The population at the end of the nineteenth century is 66P. That’s 65P more
than the original population P:


The net increase is 6,500 percent, and the answer is (E).


AVERAGES


Another classic situation with a standard approach is an averages question
like Example 7.


AVERAGE, MEDIAN, AND MODE


Median  =   middle  value   (or average of  two middle  values) Mode    =   most
frequent value; if there are two numbers that occur with equal
frequency there can be two modes
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