(D) (−i)^4 = (−i)^2 (−i)^2 = (i^2 )(i^2 ) = (−1)(−1) = 1
(E) −i^6 = (−1)(i^6 ) = (−1)(i^2 )(i^2 )(i^2 ) = (−1)(−1)(−1)(−1) = 14 . E
Translate carefully:Then solve for F in terms of R:5 . D
After a 20% discount, the original price P goes down to 0.8P. That price is
then increased by 5%, so the final price is 1.05(0.8P). The final price is
given as $71.40, so you can set up an equation and solve for the original
price P:6 . E
The class average is not simply the average of the males’ average and the
females’ average. The class average will be “weighted” in the direction of
the larger subgroup. The class average (90) is closer to the female
average (92) than to the male average (87), so there must be more
females than males. But how many exactly?