AP Statistics 2017
“software” method is based on the formula given in Chapter 11 . The second way of computing degrees of freedom ...
for a particular population proportion exist and follow a pattern similar to those of the previous two sections ...
detects the cancer at a rate different from the 85% rate claimed by its manufacturer? solution: I . Let ...
(This can also be done using 1-PropZTest in the STAT TESTS menu of the TI-83/84.) IV . The question a ...
are given in the following table. Does this study provide statistical evidence at the α = 0.01 level t ...
IV . Because P < 0.01, we have grounds to reject the null hypothesis. We have strong evidence that ...
For the following data, (a) justify the use of a two-proportion z -test for H 0 : p 1 – p ...
population standard deviations) are equal. This is hard to justify because of the lack of a strong statistic ...
III. The P -value for the test statistic in this situation will be larger for 11 degrees of free ...
Assuming that the speeds are approximately normally distributed, how many degrees of freedom will there be ...
compared. The means and standard deviations for groups A and B are determined as well as the mean and standar ...
vote for him and is overjoyed at his soon-to-be-celebrated victory. Explain carefully why Harvey should not get t ...
and that he was going to win the election. Statistically speaking (say at the 0.05 level), how happy should ...
Solutions to Practice Problems Multiple-Choice The correct answer is (d). for the one-sided alternative. ...
those getting above 80% are the same across the two populations. Free-Response 1. I . Let p 1 = the tr ...
I . Let μ = the true mean score for all students taking the exam. H (^) 0: μ = 520 (or, H 0 : μ ...
T-Test .) IV . Because P > .05, we cannot reject H 0 . We do not have strong evidence to back ...
I . Let p = the true proportion of Wednesday night television viewers who are watching “I Want to Marry ...
(from Table B). (When read directly from Table B, t = –1.48 with df = 10 is between tail probabil ...
for t = –2.84 based on df = 174, P -value = 0.0025, which is very close to the value obtained by us ...
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