and a + 2b + 4c = a + 2b + 0 = 5.
F
If a fraction equals zero, then the numerator equals zero—in other words, the denominator is irrelevant when you’re solving
the equation.
28.
C
The key here is to pick negative numbers. If the quotient—the result of dividing—of two numbers is positive, the product of
the two numbers must also be positive. Using x = −2 and y = −1:
29.
(A) −2 < 0
(B) −1 < 0
(C) (−2)(−1) = 2 > 0
(D) (−2) − (−1) = −1 < 0
(E) (−2) + (−1) = −3 < 0
F
Have faith in yourself and your diligent preparation; just because a problem uses variables twice doesn’t mean it’s twice as
hard. To find the average, take the sum of the values and divide by the number of values.
30.
C
Eliminate absolute value bars by setting up two equations. Backsolving would be a great way to solve this problem. If you’d
rather solve it algebraically, remember that there are two possibilities when dealing with an equation involving absolute
value.
31.
