New York City SHSAT 2017

(Marvins-Underground-K-12) #1
So the full equation for line l is y = −2x + 5. Plug in each answer choice to find the one that makes this equation true. Only (F)
works.

B
When you see a figure that is not drawn to scale, redraw the figure to include the aspects that are not depicted in the original
figure.

All four angles formed by the intersection of l and k are 90°. If l were parallel to m, then all four angles formed by the
intersection of m and k would also be 90°. Since l is not parallel to m, none of the angles formed by the intersection between
m and k can be equal to 90°.

45.


H


Just about all the wrong answers in this problem come from careless errors. Notice, for instance, that the radius is x − 5, not
x. You can bet that this is one mistake that un-savvy test takers will make (as well as confusing radius and diameter).

The diagram tells you that the radius of the circle is x − 5, and the question stem tells you that the circumference of the circle
is 20π. Since circumference = 2πr,

Notice that (F) is the radius − 5, (G) is the radius, and (J) is the diameter.

46.


B


Right triangles appear in all sorts of questions. Any time you’re not sure how to get a geometry question started, look for a
right triangle.

You are given the area and the width of the rectangle, from which you can find the length. A = l × w, so 48 = l × 6 and l = 8.
The longest distance between two points on the perimeter will be a diagonal of the rectangle. This diagonal forms the
hypotenuse of two right triangles, each with legs 6 and 8. You should recognize that this is a 3:4:5 right triangle, so the
hypotenuse will be 10, which is (B).

47.


G


This problem requires knowledge of ratios, rather than knowledge of area formulas. Since all of the small triangles are
equilateral, they are all identical. If you figure out the ratio of shaded triangles to unshaded triangles, you can figure out what

48.

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