PRACTICE TEST 2—PART 2
1. Part 2—Math
D
Plug in the values you have for a and b. Since a = 3 and b = −3, our equation reads 2(3) + 3(−3) + 5 = c. After doing the
multiplication, we have 6 + (−9) + 5 = c. And after doing this addition, we get 2 = c, choice (D).
51.
G
Let’s break this question down into pieces. Before midnight, Leontyne gets paid $1,000 an hour. If she starts singing at 8:30
PM, then she sings for hours before midnight. Her earnings for that time are times $1,000, or $3,500. Now let’s find
out how much she earns after midnight. Her rate increases 50% after midnight, so her hourly rate after midnight is $1,000 +
50% of $1,000. Then 50% of $1,000 is $500, so her rate per hour after midnight is $1,000 + $500 = $1,500. So she earns
$1,500 for the hour she sings after midnight. For the last step, we add that to the amount she earns before midnight, so her
total pay is $3,500 + $1,500 = $5,000, choice (G).
52.
C
Remember the order of operations here, PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition and
Subtraction). So first we do the operations inside the parentheses: 4 − 6 = −2 and 1 − 2 = −1. Now our expression reads
6(−2) + 3(−1). The next operation to do is the multiplication: 6 × (−2) = −12, and 3 × (−1) = −3. So now our expression
becomes (−12) + (−3), which is −15, choice (C).
53.
J
The key to this problem is to start at the end. Because 3 pears cost the same as 2 oranges, set up the proportion
where x is the number of pears that cost as much as 72 oranges, p is the price of 1 pear, and o is the price of 1 orange. Cross
multiply and solve for x : (2o)(xp) = (3p)(72o), so 2 x = 216 and x = 108. Now you can set up another proportion from the
other relationship described in the question: where y is the number of apples that cost as much as 108 pears and
a is the price of 1 apple. Cross multiply and solve for y : (3a)(108p) = (4p)(ya), so 4y = 324 and y = 81. Therefore, 81
apples cost the same as 72 oranges. Note that this problem could also be solved by picking a number for the cost of an
orange, solving for the cost of a pear, and then solving for the cost of an apple.
54.
D
Another order of operations question: First we have to do the operations inside the parentheses. So 8 ÷ (−4) is −2, and −12 ÷
(−3) is 4. Now our expression reads 2(−2) + 4. Next we do multiplication: 2 × (−2) = −4. Now we can do the addition: −4 +
4 = 0, choice (D).
55.
J
The probability of an event occurring is a fraction—the number of possible outcomes in which the event can occur divided by
56.
