H
The positive square roots of 64 and 36 are 8 and 6 respectively, so adding them together makes 8 + 6, or 14, choice (H).
92.
B
Draw a diagram here. You will find that there are 16 squares—3 are labeled A, 5 are labeled B, 4 are labeled C, and 2 are
labeled D. This accounts for 14 of the 16 squares. This leaves 2 squares to be labeled E. The probability of an event
occurring is a fraction—here the probability is which can be reduced to or 1 in 8, as in choice (B).
93.
F
To find the midpoint of a segment on the number line, you add the coordinates of the two endpoints and then divide the sum by
- So, the midpoint of PQ is The midpoint of RS is The distance between the two
points is the positive difference between their coordinates, or 5 − (−7) = 12, choice (F).
94.
A
Let’s call the first number x. Then the second consecutive even number is x + 2, the third consecutive even number is x + 4,
and the fourth consecutive even number is x + 6. We can represent the sum of these numbers as x + x + 2 + x + 4 + x + 6. If we
combine like terms, we have 4 x + 12. When we set this equal to 28, we get 4 x + 12 = 28. The next step is to solve for x. First
we subtract 12 from both sides, so we have 4 x = 28 − 12, or 4x = 16. Now we can divide both sides by 4 and find that x = 16
÷ 4, or 4. Since x = 4 and the largest number is x + 6, the largest number must be 4 + 6, or 10, choice (A).
95.
F
Since we have two fractions equal to each other, we can cross multiply: (28)(xy) = (x^2 )(7), or 28 xy = 7x^2. Next we will
divide both sides by 7, so we have 4 xy = x^2. Then we can divide both sides by xy, and the result is choice (F).
96.
D
Plug 2d in for c. The expression becomes 10(2d + 3) + 6(2d − 5). We can’t add 2d and 3, or subtract 5 from 2d, so the next
step is to multiply using the distributive property, so we have (10 × 2d) + (10 × 3) + (6 × 2d) + [6 × (−5)]. This can be
simplified to 20 d + 30 + 12d + (−30). Then 30 + (−30) = 0, so we end up with 20 d + 12d, or 32d, choice (D).
97.
G
Five people are being dealt 52 cards, so we will divide 52 by 5: 52 ÷ 5 = 10 remainder 2. Since we are starting with Al,
after dealing 5 cards we will be ready to start with Al again. So after 50 cards, we will be ready to start with Al again. Al
gets the 51st card, and Bo gets the 52nd card, choice (G).
98.
A
Since this question doesn’t ask for an exact answer, we can round off the answer choices. Thus, can be rounded off to
which equals or choice (A). Rounding off the other choices confirms that (A) is closest.
99.
