G o t It? 1. a. Solve th e equ atio n 4 = 2m - 5n for m. W hat are th e values of m w h e n
n = - 2 , 0 , a n d 21
b. Reasoning Solve Problem 1 by substituting x = 3 a n d x = 6 into the
eq u a tio n lOx + 5y = 80 a n d th e n solving for y in each case. Do you
prefer this m eth o d or th e m eth o d show n in Problem 1? Explain.
Thi nk
How can you solve a
literal equation fo r a
variable?
When a literal equation
contains only variables,
tre at the variables you
are not solving fo r as
constants.
W hen you rewrite literal equations, you m ay have to divide by a variable or variable
expression. W hen you do so in this lesson, assum e th a t th e variable or variable
expression is n o t equal to zero because division by zero is n o t defined.
Problem 2 Rewriting a Literal Equation With Only Variables
What equation do you get when you solve ax — b x = c for x?
ax - bx= c
Distributive Property
Divide each side by a - b, where a - b + 0.
Simplify.
x( ci -
x[a
b)
b)
X =
a — b
c
& G o t It? 2. W hat equ atio n do you get w h en you solve — t = r + px for x?
A form ula is an equ atio n th at states a relationship am ong quantities. Form ulas are
special types of literal equations. Some com m on form ulas are given below. Notice
th at som e of th e form ulas use th e sam e variables, b u t th e definitions of th e variables
are different.
Formula Name Formula Definitions of Variables
P erim eter of a rectangle P = 2 € + 2w P = perimeter, € = length, w = width
C ircum ference of a circle C = 2irr C = circu m feren ce, r = radius
Area of a rectangle A = Vw A — area, € = length, w = width
Area of a triangle A = ^bh A = area, b = base, h = height
Area of a circle A — 77T2 A — area, r = radius
D istance traveled d = rt d = distance, r = rate, t = tim e
Temperature
V
C = | ( F — 32) C = degrees Celsius, F = degrees F ahrenheit
J
110 Ch ap t er 2 So l v i n g Eq u a t i o n s