Algebra 1 Common Core Student Edition, Grade 8-9

(Marvins-Underground-K-12) #1

  1. Biology A h o r s e ’s b o d y te m p e r a t u r e T is c o n s id e r e d t o b e n o r m a l i f i t is w i t h i n a t
    le a s t 0.9°F o f 99.9°F. F in d t h e r a n g e o f n o r m a l b o d y te m p e r a t u r e s f o r a h o rs e.

  2. Biking Y o u r fr ie n d rid e s h is b ik e t o w a r d y o u a n d th e n passes b y y o u a t a c o n s ta n t
    sp e e d. H is d is ta n c e d ( in fe e t) fr o m y o u t s e c o n d s a f t e r h e s t a r t e d r i d i n g h i s b i k e is g i v e n
    by d = 120 0 - 1 8 f|. W h a t d o e s th e 200 i n th e e q u a tio n re p re se n t? W h a t d o e s th e 1 8 in
    the equ a tio n represent? A t w h a t tim e(s) is he 120 ft fro m you?


E rro r A n alys is F in d a n d c o r r e c t t h e m is t a k e i n s o lv in g e a c h e q u a t io n
or inequality.

64 ^ 3 = 2 ^ 65‘

Open-Ended Write an absolute value equation that has 2 a n d 6 as so lu tio n s.
Reasoning Explain why you can rewrite \x + 5| > 1 as a c o m p o u n d in e q u a lity
in v o lv in g or.

Polling A c c o r d in g t o a p o l l f o r a n u p c o m in g s c h o o l b o a r d e le c tio n , 4 0 % o f v o te r s
a re l ik e ly t o v o te f o r t h e in c u m b e n t. T h e p o l l s h o w s a m a r g in o f e r r o r o f
± 3 percentage points. W rite and solve an absolute value equation to find the least
a n d t h e g re a te s t p e r c e n ts o f v o te r s v li k e l y to v o te f o r th e in c u m b e n t.
Banking T h e o f f ic ia l w e ig h t o f a n ic k e l is 5 g, b u t t h e a c tu a l w e ig h t c a n v a r y f r o m
t h is a m o u n t b y u p to 0 .1 9 4 g. S u p p o s e a b a n k w e ig h s a r o l l o f 4 0 n ic k e ls. T h e
w r a p p e r w e ig h s 1.5 g.
a. W h a t is t h e ra n g e o f p o s s ib le w e ig h ts f o r th e r o l l o f n ic k e ls?
b. Reasoning If all of the nickels in the roll each w eigh the official am ount, then
t h e r o l l ’s w e ig h t is 4 0 (5 ) + 1.5 = 2 0 1 .5 g. Is i t p o s s ib le f o r a r o l l t o w e ig h 2 0 1 .5 g
a n d c o n t a in n ic k e ls t h a t d o n o t w e ig h t h e o f f ic ia l a m o u n t? E x p la in.

Oil Production A n o i l r e f in e r y a im s t o p ro c e s s 9 0 0 ,0 0 0 b a r r e ls o f o i l p e r d a y. T h e
d a ily p r o d u c t io n v a r ie s b y u p t o 5 0 ,0 0 0 b a r r e ls f r o m t h is g o a l, in c lu s iv e. W h a t a re
the m in im u m and m a x im u m n u m b e rs o f barrels o f o il processed each day?

W r i t e a n a b s o lu t e v a lu e i n e q u a l i t y t h a t r e p r e s e n t s e a c h s e t o f n u m b e r s.

71. a ll r e a l n u m b e r s le ss t h a n 4 u n it s f r o m 0 72. a ll r e a l n u m b e r s a t m o s t 7 u n it s f r o m 0


  1. all real num bers more than 2 u n its fro m 6 74. a ll r e a l n u m b e r s a t le a s t 2 u n its fro m -1


CB3 75. Manufacturing The ideal diam eter o f a piston fo r one type o f car engine is
9 0 .0 0 0 m m. T h e a c tu a l d ia m e t e r c a n v a r y f r o m t h e id e a l b y a t m o s t 0 .0 0 8 m m. W h a t
is th e r a n g e o f a c c e p ta b le d ia m e te r s f o r t h e p is to n?


  1. Farm Maintenance F o r s a fe ty , th e r e c o m m e n d e d h e ig h t o f a h o r s e fe n c e is 5 ft.
    B e c a u s e o f u n e v e n g r o u n d s u rfa c e s , t h e a c tu a l h e ig h t o f th e fe n c e c a n v a r y f r o m
    t h is r e c o m m e n d a t io n b y u p t o 3 in. W r it e a n d s o lv e a n a b s o lu te v a lu e e q u a t io n to
    f i n d th e m a x im u m a n d m i n i m u m h e ig h ts o f th e fe n c e.


(& 66.
@67.

68.

@69.

70.

2 1 2 Chapter 3 Solving Inequalities

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