Co n cep t Byt e
Use W it h Lesson 9-3
Finding Roots
Co m m o n Co r e St a t e St a n d a r d s
F-IF.C.7a Graph linear and quadratic functions and
show intercepts, maxima, and minima. A ls o A-REI.B.4
MP 5
The solutions of a quadratic equation are the x-intercepts of the graph of the related
quadratic function. Recall that the solutions and the related x-intercepts are often
called roots of the equation or zeros of the function.
Activity
Use a graphing calculator to solve x 2 - 6x + 3 = 0.
Step 1 Enter y = x2 - 6x + 3 on the Y= screen. Use the CALC feature. Select ZERO.
The calculator will graph the function.
Step 2 Step 3 Step 4
MATHEMATICAL
PRACTICES
\
1 Zer0
1 X = .55051026- Y = 0
Move the cursor to the
left of the first x-intercept.
Press ^552^ to set the left
bound.
Move the cursor slightly to
the right of the intercept.
Press to set the right
bound.
Press 4323^ to display the
first root, which is about
0.55.
Repeat Steps 2-4 for the second x-intercept. The second root is about 5.45. So the
solutions are about 0.55 and 5.45.
Suppose you cannot see both of the x-intercepts on
your graph. You can find the values of y that are close
to zero by using the TABLE feature. Use the TBLSET
feature to control how the table behaves. Set ATBL
to 0.5. Set INDPNT: and DEPEND: to AUTO. The
calculator screen at the right shows part of the table for
y = 2x2 - 48x + 285.
X Yi
10.5 11
11.5 12
12.5
13
BW i
(^1.5^
-2.5
<fc
The graph crosses the x-axis
when the values for y change
signs. So the range of x-values
should include 10.5 and 13.5.
1
X = 13. 5 V ~ 1 -------------'
Ex e r c i se s
Use a graphing calculator to solve each equation. Round your solutions to the
nearest hundredth.
- x2- 6 x - 16 = 0
- x2 — 18x + 5 = 0
- 2x2 + x — 6 = 0
- 0.25x2 - 8x - 45 = 0
- |x2 + 8x - 3 = 0
- 0.5x2 + 3x — 36 = 0
c
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