- No; there is no variable in the radicand. 5. The graph
of y = Vx - 1 is the graph of y = Vx shifted to the
right 1 unit. 6. Yes; the domain includes all the values
of x such that the radicand has a value greater than or
equal to zero, so for b > 0 , the domain of y = Vx + b
is x > -b, which includes negative values.
Ex e r c i se s 7.x>0 9. x>7 11.x>-2
13. x< 18 15. x>4
fi 0 /
/ / / / X 0
Xm
(^0) 0 ]
[ (^1) 4 I
[ 4 8 I
y
o
X
\
—r-t
h V
00
1 4.4
610.8
V
X y
00
3
- 3 4
V y
h > 5.1 m
- A 29. B
31. y X
0
33.
41a. f
P
0 40
47.
X fix)
I 0 0
[ 1 4
[ 2 5. 7
[ 4 8
J
r
X y
( 0^0
( 2 1
( 4 1. 4
I 8^2
49.
51.
X fix)
-2 -4
-1 -3
2-2
X y
-3 1 )
-2 2.4 ]
-1 3 j
(^0) 34 i
y
-ir
X
- y
r X
0
b. about 45 lb/in.
- about 2800 m /s
- fi 0 jf'
xy
/f X
0
y
X
b
- fi i) X
0
53a. No; the graph does not pass the vertical-line test,
b. The graph of y = V * is the first-quadrant portion of
the graph of x = y 2. c. y = - Vx