Remember that when we solve an equation, our primary goal is to isolate the
variable on one side of the equation.
Applying Both Properties of Equality to Solve an EquationSolve.
Step 1 There are no parentheses, fractions, or decimals in this equation, so this step
is not necessary.
Step 2 Subtract 5 from each side.
Combine like terms.Step 3 Divide each side by
Step 4 Check by substituting for xin the original equation.
CHECK Original equation
Let
Multiply.✓ True
The solution, - 2 , checks, so the solution set is 5 - 26. NOW TRY
17 = 17
12 + 5 17
- 61 - 22 + 5 17 x=-2.
- 6 x+ 5 = 17
- 2
x=- 2
- 6.
- 6 x
- 6
=
12
- 6
- 6 x= 12
- 6 x+ 5 - 5 = 17 - 5
- 6 x+ 5 = 17
- 6 x+ 5 = 17
EXAMPLE 1
98 CHAPTER 2 Linear Equations and Inequalities in One Variable
NOW TRY
EXERCISE 1
Solve. 7 + 2 m=- 3
NOW TRY
EXERCISE 2
Solve. 2 q+ 3 = 4 q- 9
Our goal is
to isolate x.Applying Both Properties of Equality to Solve an EquationSolve.
Step 1 There are no parentheses, fractions, or decimals in the equation.
Step 2 Subtract 5xfrom each side.
Combine like terms.
Subtract 2 from each side.
Combine like terms.Step 3 Divide each side by
Step 4 Check by substituting 5 for xin the original equation.
CHECK Original equation
Let.
Multiply.✓ True
The solution, 5, checks, so the solution set is 556. NOW TRY
17 = 17
15 + 2 25 - 8
3 152 + 2 5 152 - 8 x= 5
3 x+ 2 = 5 x- 8
x= 5
- 2.
- 2 x
- 2
=
- 10
- 2
- 2 x=- 10
- 2 x+ 2 - 2 =- 8 - 2
- 2 x+ 2 =- 8
3 x+ 2 - 5 x= 5 x- 8 - 5 x
3 x+ 2 = 5 x- 8
3 x+ 2 = 5 x- 8
EXAMPLE 2
NOW TRY ANSWERS
- 5 - 56 2. 566
Our goal is
to isolate x.http://www.ebook777.com
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