Beginning Algebra, 11th Edition

(Marvins-Underground-K-12) #1
Solving an Equation with Fractions as Coefficients

Solve


Step 1 The LCD of all the fractions in the equation is 6.


Multiply.
Combine like terms.

Step 2 Add x.


Combine like terms.

Step 3 Divide by 2.


Step 4 CHECK Original equation


Let

Multiply.

✓ True


The solution, - 6 , checks, so the solution set is 5 - 66. NOW TRY


- 1 =- 1


- 4 + 3  1 - 2


x=- 6.


2


3


1 - 62 -


1


2


1 - 62 -


1


6


1 - 62 - 2


2


3


x-


1


2


x=-


1


6


x- 2


x=- 6


2 x


2


=


- 12


2


2 x=- 12


x+x=-x- 12 + x


x=-x- 12


4 x- 3 x=-x- 12


6 a


2


3


xb + 6 a-


1


2


xb = 6 a-


1


6


xb + 61 - 22


6 a


2


3


x-


1


2


xb = 6 a-


1


6


x- 2 b


2


3


x-


1


2


x=-


1


6


x- 2


2

3 x-


1

2 x=-^


1

6 x-2.


EXAMPLE 6

SECTION 2.3 More on Solving Linear Equations 101


CAUTION When clearing an equation of fractions, be sure to multiply every


term on each side of the equation by the LCD.


NOW TRY
EXERCISE 6
Solve.


1
2

x+

5

8

x=

3

4

x- 6

Multiply each side by
6, the LCD.
Distributive property;
multiply eachterm
inside the parentheses
by 6.

Solving an Equation with Fractions as Coefficients

Solve.


Step 1


Distributive property

Multiply.
Distributive property

- 4 x+ 7 = 15 Combine like terms.


5 x+ 25 - 9 x- 18 = 15


5 1 x+ 52 - 9 1 x+ 22 = 15


15 B


1


3


1 x+ 52 R + 15 B-


3


5


1 x+ 22 R= 15112


15 B


1


3


1 x+ 52 -


3


5


1 x+ 22 R= 15112


1


3


1 x+ 52 -


3


5


1 x+ 22 = 1


1

3 1 x+^52 -


3

5 1 x+^22 =^1


EXAMPLE 7

The fractions have
been cleared.

Clear the fractions.
Multiply by 15, the LCD.

NOW TRY ANSWER



  1. 5 - 166


Pay particular
attention here.

= 51 x+ 52

= 15 # 13 # 1 x+ 52


15 C^13 1 x+ 52 D
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