Beginning Algebra, 11th Edition

(Marvins-Underground-K-12) #1
Finding the Measure of an Angle

Find the measure of an angle whose complement is five times its measure.


Step 1 Readthe problem. We must find the measure of an angle, given information


about the measure of its complement.


Step 2 Assign a variable.


Let the degree measure of the angle.


Then the degree measure of its complement.


Step 3 Write an equation.


Measure of the 5 times the measure
complement is of the angle.

5 x


Step 4 Solve. Add x.


Combine like terms.

Divide by 6.

,or


Step 5 State the answer.The measure of the angle is.


Step 6 Check. If the angle measures , then its complement measures


, which is equal to five times , as required.


NOW TRY

Finding the Measure of an Angle

Find the measure of an angle whose supplement is 10° more than twice its complement.


Step 1 Read the problem. We are to find the measure of an angle, given


information about its complement and its supplement.


Step 2 Assign a variable.


Let


Then


and


We can visualize this information using a sketch. See FIGURE 6.


180 - x= the degree measure of its supplement.


90 - x= the degree measure of its complement,


x= the degree measure of the angle.


EXAMPLE 9

90°- 15°= 75° 15°


15°


15°


15 =x x= 15


90


6


=


6 x


6


90 = 6 x


90 - x+x= 5 x+x


90 - x =


90 - x=


x=


EXAMPLE 8

114 CHAPTER 2 Linear Equations and Inequalities in One Variable


If xrepresents the degree measure of an angle, then


180 x represents the degree measure of its supplement.


90 x represents the degree measure of its complement.


PROBLEM-SOLVING HINT

NOW TRY
EXERCISE 8
Find the measure of an angle
whose complement is twice
its measure.


x

Complement
of x:
90 2 x
xx x x

Supplement of x:
180 2 x
x

FIGURE 6

NOW TRY ANSWER



  1. 30°


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