Beginning Algebra, 11th Edition

(Marvins-Underground-K-12) #1

SECTION 4.5 Solving Systems of Linear Inequalities^283


Solving a System of Linear Inequalities

Graph the solution set of the system.


FIGURE 15shows the graphs of both


and Dashed lines show that the


graphs of the inequalities do not include their


boundary lines. Use as a test point to deter-


mine the region to shade for each inequality.


The solution set of the system is the region with


the gray shading. The solution set does not include


either boundary line.


NOW TRY

Solving a System of Three Linear Inequalities

Graph the solution set of the system.


Recall that is a vertical line through the


point , and is a horizontal line through


the point. The graph of the solution set is the


shaded region in FIGURE 16, including all boundary


lines. (Here, use as a test point to confirm that


the correct region is shaded.)


1 3, 2 2


1 0, 4 2


1 2, 0 2 y= 4


x= 2


y... 4


xÚ 2


4 x- 3 y... 8


EXAMPLE 3

1 0, 0 2


2 x+ y 6 2.


x-y 7 5


2 x+y 62


x-y 75


EXAMPLE 2

NOW TRY

NOTEWe usually do all the work on one set of axes. In the remaining examples,


only one graph is shown. Be sure that the region of the final solution is clearly


indicated.


NOW TRY
EXERCISE 3
Graph the solution set of the
system.


y... 4

xÚ- 2

x-y 62

NOW TRY
EXERCISE 2
Graph the solution set of the
system.


x- 2 y 60

2 x+ 5 y 710

x

y

2 x + y < 2

x – y > 5

Solution set

0

2
5

–5

FIGURE 15

x

y
2
0 5
2 x + 5y > 10
x – 2y < 0

NOW TRY ANSWERS
2.






x

y
4

–2 (^0) x – y < 2
y ≤ 4
x ≥ –2


We can graph the solution set of the following system with a calculator.


To graph the first inequality, we direct the calculator to shade belowthe line


( because of the symbol).


To graph the second inequality, we direct the calculator to shade abovethe line


( because of the symbol).


FIGURE 17(a)on the next page shows these directions on a TI-83/84 Plus calculator.


Graphing in the standard viewing window gives the screen in FIGURE 17(b).


Y 2 =-2X- 5 7


Y 1 =3X + 2 6


y7- 2 x- 5


y 63 x+ 2


CONNECTIONS


x

y

4 x – 3y ≤ (^8) x ≥ 2
y ≤ 4
Solution set
0
2
2
FIGURE 16

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