Beginning Algebra, 11th Edition

(Marvins-Underground-K-12) #1
Solving a Quadratic Equation with a Common Factor

Solve


Standard form
Factor out 2.
Divide each side by 2.
Factor.
Zero-factor property
Solve each equation.

Checkeach solution to verify that the solution set is E. NOW TRY


5

2 , 4F


p=


5


2


2 p= 5 p= 4


2 p- 5 = 0or p- 4 = 0


12 p- 521 p- 42 = 0


2 p^2 - 13 p+ 20 = 0


212 p^2 - 13 p+ 202 = 0


4 p^2 - 26 p+ 40 = 0


4 p^2 + 40 = 26 p


4 p^2 + 40 = 26 p.


EXAMPLE 3

CHECK Let Let


✓ True ✓ True


Both solutions check, so the solution set is


(b)


Subtract yand 20.
Factor.
Zero-factor property
Solve each equation.

Checkeach solution to verify that the solution set is 5 - 4, 5 6. NOW TRY


y= 5 or y=- 4


y- 5 =0or y+ 4 = 0


1 y- 521 y+ 42 = 0


y^2 - y- 20 = 0


y^2 =y+ 20


5 2, 3 6.


- 6 =- 6 - 6 =- 6


4 - 10 - 6 9 - 15 - 6


22 - 5122 - 6 3 2 - 5132 - 6


x^2 - 5 x=- 6 x 2 - 5 x=- 6


x= 2. x= 3.


394 CHAPTER 6 Factoring and Applications


NOW TRY
EXERCISE 2
Solve .t^2 =- 3 t+ 18


NOW TRY
EXERCISE 3
Solve. 10 p^2 + 65 p= 35


Write this equation
in standard form.
Standard form

Solving a Quadratic Equation by Factoring
Step 1 Write the equation in standard form— that is, with all terms on
one side of the equals symbol in descending powers of the variable
and 0 on the other side.
Step 2 Factorcompletely.
Step 3 Use the zero-factor propertyto set each factor with a variable
equal to 0.
Step 4 Solvethe resulting equations.
Step 5 Checkeach solution in the original equation.

This 2 is not
a solution of
the equation.

NOW TRY ANSWERS



  1. 5 - 6, 3 6 3.E-7,^12 F


NOTE Not all quadratic equations can be solved by factoring. A more general


method for solving such equations is given in Chapter 9.


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