Beginning Algebra, 11th Edition

(Marvins-Underground-K-12) #1
Solving Quadratic Equations with Double Solutions

Solve each equation.


(a)


Factor the perfect square trinomial.

Zero-factor property

Because the two factors are identical, they both lead to the same solution. (This is


called a double solution.)


Add 11.

CHECK


Let.

✓ True


The solution set is.


(b)


Standard form
Factor the perfect square trinomial.
Zero-factor property
Solve the equation.

is a double solution.

Checkby substituting in the original equation. The solution set is


NOW TRY

E


5

3 F.


5
3

5

t= 3


5


3


3 t= 5


3 t- 5 = 0 or 3 t- 5 = 0


13 t- 522 = 0


9 t^2 - 30 t+ 25 = 0


9 t^2 - 30 t=- 25


5116


0 = 0


121 - 242 + 121  0


112 - 221112 + 121  0 z= 11


z^2 - 22 z+ 121 = 0


z= 11


z- 11 = 0 or z- 11 = 0


1 z- 1121 z - 112 = 0 a^2 =a#a


1 z- 1122 = 0


z^2 - 22 z+ 121 = 0


EXAMPLE 5

396 CHAPTER 6 Factoring and Applications


CAUTION Each of the equations in Example 5has only onedistinct solution.


There is no need to write the same number more than once in a solution set.


OBJECTIVE 2 Solve other equations by factoring. We can also use the zero-


factor property to solve equations that involve more than two factors with variables.


(These equations are notquadratic equations. Why not?)


Solving Equations with More Than Two Variable Factors

Solve each equation.


(a)


Factor out 6z.
Factor

By an extension of the zero-factor property, this product can equal 0 only if at least


one of the factors is 0. Write and solve three equations, one for each factor with a


variable.


6 z 1 z+ 121 z- 12 = 0 z^2 - 1.


6 z 1 z^2 - 12 = 0


6 z^3 - 6 z = 0


EXAMPLE 6

NOW TRY
EXERCISE 5
Solve.


4 x^2 - 4 x+ 1 = 0

NOW TRY ANSWER



  1. E^12 F


http://www.ebook777.com
http://www.ebook777.com
Free download pdf