73.
74.
75.
76.
77.Concept Check If you are solving a formula for the letter k, and your steps lead to the
equation , what would be your next step?
78.Refer to Example 7,and show that 7 is a solution.
Solve each formula for the specified variable. See Examples 8 and 9.
- for F 80. for E 81. for a
- for R 83. for R 84. for r
- for 86. for S
- for a 88. for B
- for y 90. for q
- for t 92. for r
- for z 94. for p
- 5
y+ 2
- 5
- r
y- 2
=
3
y^2 - 4
for r
t
x- 1
- 2
x+ 1
=
1
x^2 - 1
for t
- 3 t-
4
p
=
6
s
9 x+
3
z
=
5
y
5
p
+
2
q
+
3
r
= 1
2
r
+
3
s
+
1
t
= 1
3
k
=
1
p
+
1
q
1
x
=
1
y
1
z
h=
2 a
B+b
d=
2 S
n 1 a+L 2
d=
2 S
n 1 a+L 2
h= a
2 a
B+b
I=
E
R+r
I=
E
R+r
I=
kE
R
m=
kF
a
I=
kE
R
m=
kF
a
kr-mr=km
3
r^2 +r- 2
1
r^2 - 1
=
7
21 r^2 + 3 r+ 22
x+ 4
x^2 - 3 x+ 2
- 5
x^2 - 4 x+ 3
=
x- 4
x^2 - 5 x+ 6
m
m^2 +m- 2
+
m
m^2 - 1
=
m
m^2 + 3 m+ 2
3 x
x^2 + 5 x+ 6
=
5 x
x^2 + 2 x- 3
2
x^2 +x- 2
- 13
t^2 + 6 t+ 8
4
t+ 2
=
3
2 t+ 8
4
3 x+ 6
3
x+ 3
=
8
x^2 + 5 x+ 6
x
x- 3
+
4
x+ 3
=
18
x^2 - 9
1
x+ 4
+
x
x- 4
=
- 8
x^2 - 16
10 x- 24
x
=x
8 x+ 3
x
= 3 x
5 t+ 1
3 t+ 3
=
5 t- 5
5 t+ 5
+
3 t- 1
t+ 1
x
2 x+ 2
=
- 2 x
4 x+ 4
+
2 x- 3
x+ 1
5
p- 2
= 7 -
10
p+ 2
2
x- 1
2
3
=
- 1
x+ 1
m
8 m+ 3
=
1
3 m
5 x
14 x+ 3
=
1
x
2 x
x^2 - 16
- 2
x- 4
=
4
x+ 4
2 p
p^2 - 1
=
2
p+ 1
- 1
p- 1
2 k+ 3
k+ 1
- 3 k
2 k+ 2
=
- 2 k
2 k+ 2
x
3 x+ 3
=
2 x- 3
x+ 1
- 2 x
3 x+ 3
464 CHAPTER 7 Rational Expressions and Applications
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