Beginning Algebra, 11th Edition

(Marvins-Underground-K-12) #1

OBJECTIVE 2 Find the product of two negative numbers. Look at another


pattern.


- 51 - 12 =?


- 5102 = 0


- 5112 =- 5


- 5122 =- 10


- 5132 =- 15


- 5142 =- 20


50 CHAPTER 1 The Real Number System


The products
increase by 5.

The numbers in color on the left of the equals symbol decrease by 1 for each step


down the list. The products on the right increase by 5 for each step down the list. To


maintain this pattern, should be 5 more than or 5 more than 0, so


The pattern continues with


and so on, which suggests the next rule.


- 51 - 52 = 25 ,


- 51 - 42 = 20


- 51 - 32 = 15


- 51 - 22 = 10


- 51 - 12 = 5.


- 51 - 12 - 5102 ,


Multiplying Two Negative Numbers

For any positive real numbers xand y,


That is, the product of two negative numbers is positive.


Example: - 51 - 42 = 20


x 1 y 2 xy.


NOW TRY
EXERCISE 2
Find the product.






1

7

a-

5

2

b

NOW TRY ANSWER



  1. 145


Multiplying Two Negative Numbers

Find each product, using the multiplication rule given in the box.


(a) (b)


(c) (d) NOW TRY


The following box summarizes multiplying signed numbers.


-


2


3


a-


3


2


b =


2


3


#^3


2



  • 81 - 12 = 8 # 1 = 8 = 1

  • 91 - 22 = 9 # 2 = 18 - 61 - 122 = 6 # 12 = 72


EXAMPLE 2

Multiplying Signed Numbers

The product of two numbers having the samesign is positive.


The product of two numbers having differentsigns is negative.


OBJECTIVE 3 Identify factors of integers.The definition of factor from


Section 1.1can be extended to integers. If the product of two integers is a third inte-


ger, then each of the two integers is a factorof the third. The table on the next page


shows examples.


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