Graphing a Linear Inequality
Graph
First graph the boundary line, shown in FIGURE 39. The points of the boundary
line do not belong to the inequality (because the inequality symbol is
not ). For this reason, the line is dashed. Now solve the inequality for y.
Subtract x.
Multiply by. Change
Because of the is greater thansymbol that occurs when
the inequality is solved for y,shade abovethe line.
CHECK Choose a test point not on the line, say,.
Let and.
✓ True
This result agrees with the decision to shade above the
line. The solution set, graphed in FIGURE 39, includes
only those points in the shaded half-plane (not those
on the line).
06 4
0 - 31026 x= 0 y= 0
?
4
x- 3 y 6 4
1 0, 0 2
y 7 -^136 to 7.
1
3
x-
4
3
- 3 y6-x+ 4
x- 3 y 6 4
...
x- 3 y 6 4 6 ,
x- 3 y 6 4.
EXAMPLE 2
SECTION 3.4 Linear Inequalities in Two Variables 177
In practice, the graphs in FIGURES 40(a) AND (b)are graphed on the same axes.
CHECK Using FIGURE 40(c), choose a test point from each of the four regions
formed by the intersection of the boundary lines. Verify that only ordered pairs in the
heavily shaded region satisfy bothinequalities. NOW TRY
NOW TRY
EXERCISE 2
Graph. 3 x-y 66
x
y
(0, 0)
0
2
4
x – 3y < 4
x – 3 y = 4
FIGURE 39
OBJECTIVE 2 Graph the intersection of two linear inequalities. A pair of
inequalities joined with the word andis interpreted as the intersection of the solution
sets of the inequalities. The graph of the intersection of two or more inequalities is
the region of the plane where all points satisfy all of the inequalities at the same time.
Graphing the Intersection of Two Inequalities
Graph and
To begin, we graph each of the two inequalities and sepa-
rately, as shown in FIGURES 40(a) AND (b). Then we use heavy shading to identify the
intersection of the graphs, as shown in FIGURE 40(c).
2 x+ 4 yÚ 5 xÚ 1
2 x+ 4 yÚ 5 xÚ1.
EXAMPLE 3
x
y
0 5
2
5
4
2 x + 4y ≥ 5
x
y
–2 0
2
–2 x ≥ 1
x
y
0
2 x + 4y ≥ 5
and x ≥ 1
(a) (b) (c)
FIGURE 40
NOW TRY ANSWERS
–6
y
3 x – y < 6
0
x
2
NOW TRY
NOW TRY
EXERCISE 3
Graph and .x+y 63 y... 2
x
y
0 3
3
2
x + y < 3
and y Ä 2